Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.3 - Limits and Continuity: Algebraic Viewpoint - Exercises - Page 718: 44

Answer

the limit does not exist

Work Step by Step

1. f is a closed function (we know by Th.10.1 that it is continuous), that is, L= $\displaystyle \lim_{x\rightarrow a}f(x)$ = $f(a)$, for all a from the domain of f. 2. evaluating: $f(-1)$, (plugging $x=-1$) , we see that $x=-1$ is NOT in the domain of f. As $x\rightarrow-1,$ (we approach $-1$ from either side) the numerator approaches -2, which is negative, The denominator, however, has different signs when we approach -1 from different sides. Evaluate for -0.99 ( denom.=-0.0099$) $and -1.01 (denom=+0.0101) to confirm. The limit takes the determinate form $\displaystyle \frac{k}{0^{\pm}}=\pm\infty $, but one side diverges to $-\infty$, and the other to $+\infty$, so the limit does not exist
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