Answer
determinate,
$0$
Work Step by Step
When x$\rightarrow-\infty$,
$ x^{2}\rightarrow+\infty$,
$2x^{2}\rightarrow+\infty $, determinate form: $ k(\pm\infty)=\pm\infty,$
$ 3+2x^{2}\rightarrow+\infty$, determinate form: $ k\pm\infty=\pm\infty$,
so the whole fraction is of the determinate form $\displaystyle \pm\frac{k}{\infty}=0$,
so, the limit equals 0.