Answer
determinate,
diverges to $+\infty$
Work Step by Step
See the table: "Some Determinate and lndeterminate Forms" and$, $after plugging in the value for x, recognize that the limit is initially in the form
$ k\pm\infty=\pm\infty$ (determinate)
(when x$\rightarrow-\infty$,
$ x^{2}\rightarrow+\infty$,
$3x^{2}\rightarrow+\infty $,
$6+3x^{2}\rightarrow+\infty )$
so the limit diverges to $+\infty$.