Answer
diverges to $-\infty$
Work Step by Step
1. f is a closed function (we know by Th.10.1 that it is continuous), that is, L= $\displaystyle \lim_{x\rightarrow a}f(x)$ = $f(a)$,
for all a from the domain of f.
2. evaluating: $f(0)$, (plugging $x=0$) , we see that $x=0$ is NOT in the domain of f..
case 3 : recognize the determinate form $\displaystyle \frac{k}{0^{\pm}}=\pm\infty $
as $x\rightarrow 0^{+},$
the numerator is 1, positive, but
the denominator is negative because for very small x, $x^{2}
