Answer
does not exist
Work Step by Step
1. f is a closed function (we know by Th.10.1 that it is continuous), that is, L= $\displaystyle \lim_{x\rightarrow a}f(x)$ = $f(a)$,
for all a from the domain of f.
2. evaluating: $f(-1)$, (plugging $x=-1$) , we see that $x=-1$ is NOT in the domain of f.
case 3 : recognize the determinate form $\displaystyle \frac{k}{0^{\pm}}=\pm\infty $
as $x\rightarrow-1,$
the numerator approaches 2, which is positive,
but,
the denominator has a problem:
when approaching from the left, it is negative,
and when approaching from the right, it is positive...
so one side diverges to $-\infty$, and the other to +$\infty$....
The limit does not exist
