Answer
$dz=1.22$
Work Step by Step
We are given $z=6x^{2}-7y^{2}+4xy$
$f_{x}(x,y)=12x+4y$
$f_{y}(x,y)=-14y+4x$
By the definition $dz=f_{x}(x,y).dx+f_{y}(x,y).dy$
with $x=3; y=-1; dx=0.03; dy=0.01$
we have $dz=(12x+4y)0.03+(-14y+4x)0.01$
$dz=1.22$