Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 9 - Multiveriable Calculus - Chapter Review - Review Exercises - Page 519: 59

Answer

$dz=1.22$

Work Step by Step

We are given $z=6x^{2}-7y^{2}+4xy$ $f_{x}(x,y)=12x+4y$ $f_{y}(x,y)=-14y+4x$ By the definition $dz=f_{x}(x,y).dx+f_{y}(x,y).dy$ with $x=3; y=-1; dx=0.03; dy=0.01$ we have $dz=(12x+4y)0.03+(-14y+4x)0.01$ $dz=1.22$
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