Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 61

Answer

$e^{4.41763}=82.9$

Work Step by Step

For $a>0, a\neq 1$, and $x>0,\qquad y=\log_{a}x$ means $a^{y}=x$. $.................................$ $\ln 82.9=\log_{e}82.9=4.41763 \qquad$ means the same as $e^{4.41763}=82.9$
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