Answer
$(-\infty, -4)\cup(4, \infty)$
Work Step by Step
$y=\ln(x^{2}-16)$
For y to be defined,
the argument of the logarithm must be positive,
$x^{2}-16>0$
$x^{2}>16$
$x>4$ or $x\lt-4$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 30
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
