Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 30

Answer

$(-\infty, -4)\cup(4, \infty)$

Work Step by Step

$y=\ln(x^{2}-16)$ For y to be defined, the argument of the logarithm must be positive, $x^{2}-16>0$ $x^{2}>16$ $x>4$ or $x\lt-4$
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