Answer
True.
Work Step by Step
Comparing the graphs,
As x grows greater, for $a >0,$
$e^{x+a} =e^{x}\cdot e^{a}$ is greater than $e^{x}$
much more than
$\ln(x+a)$ is greater than $\ln x$
The statement is true
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 17
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
