Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 51



Work Step by Step

$2^{x+2}=\displaystyle \frac{1}{8}\qquad \color{blue}{\text{ ...recognize } 2^{3}=8}$ $2^{x+2}=\displaystyle \frac{1}{2^{3}}\qquad \color{blue}{\text{ ..apply } a^{-n}=\frac{1}{a^{n}}}$ $2^{x+2}=2^{-3}\qquad \color{blue}{\text{ ...equate the exponents } }$ $x+2=-3$ $x=-5$
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