## Calculus with Applications (10th Edition)

$[2, \infty)$
$y=\displaystyle \frac{\sqrt{x-2}}{2x+3}$ For y to be defined, 1. the radicand in the numerator must not be negative, and 2. the denominator must not be zero $\left[\begin{array}{lll} 1. & & 2.\\ x-2\geq 0 & & 2x+3\neq 0\\ x\geq 2 & & 2x\neq-3\\ & & x\neq-\frac{3}{2} \end{array}\right]$ Domain: $[2, \infty)$