Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - Chapter Review - Review Exercises - Page 113: 28

Answer

$[2, \infty)$

Work Step by Step

$y=\displaystyle \frac{\sqrt{x-2}}{2x+3}$ For y to be defined, 1. the radicand in the numerator must not be negative, and 2. the denominator must not be zero $\left[\begin{array}{lll} 1. & & 2.\\ x-2\geq 0 & & 2x+3\neq 0\\ x\geq 2 & & 2x\neq-3\\ & & x\neq-\frac{3}{2} \end{array}\right]$ Domain: $[2, \infty)$
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