Answer
$5570.6
Work Step by Step
We are given $P=41000, i=\frac{0.12}{2}=0.06, n=10$
the formula is $P=R[\frac{1-(1+i)^{-n}}{i}]$
so $\rightarrow R=\frac{P}{[\frac{1-(1+i)^{-n}}{i}]}$
$=\frac{41000}{[\frac{1-(1+0.06)^{-10}}{0.06}]}\approx \$5570.6$