Answer
$3416.7
Work Step by Step
We are given $S=80.000, i=\frac{0.06}{2}=0.03, n=9\times2=18$
$S=R[\frac{(1+i)^{n}-1}{i}]$
so $\rightarrow R=\frac{80.000}{[\frac{(1+0.03)^{18}-1}{0.03}]} \approx \$3416.7$
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