Answer
$11118.4
Work Step by Step
We are given $R=10000, i=0.04, n=15$
the formula is $P=R[\frac{1-(1+i)^{-n}}{i}]$
so $\rightarrow P=10000[\frac{1-(1+0.04)^{-15}}{0.04}] \approx \$ 11118.4$
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