Answer
$39434.4
Work Step by Step
We are given $P=5000, i=0.06, n=11$
the formula is $P=R[\frac{1-(1+i)^{-n}}{i}]$
so $\rightarrow P=5000[\frac{1-(1+0.06)^{-11}}{0.06}] \approx \$ 39434.4$
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