Answer
$476.9
Work Step by Step
We are given $P=2500, i=\frac{0.16}{4}=0.04, n=6$
the formula is $P=R[\frac{1-(1+i)^{-n}}{i}]$
so $\rightarrow R=\frac{P}{[\frac{1-(1+i)^{-n}}{i}]}$
$=\frac{2500}{[\frac{1-(1+0.04)^{-6}}{0.04}]}\approx \$476.9$