## Calculus with Applications (10th Edition)

Published by Pearson

# Chapter 12 - Sequences and Series - 12.2 Annuities: An Application of Sequences - 12.2 Exercises - Page 622: 25

$476.9 #### Work Step by Step We are given$P=2500, i=\frac{0.16}{4}=0.04, n=6$the formula is$P=R[\frac{1-(1+i)^{-n}}{i}]$so$\rightarrow R=\frac{P}{[\frac{1-(1+i)^{-n}}{i}]}=\frac{2500}{[\frac{1-(1+0.04)^{-6}}{0.04}]}\approx \$476.9$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.