Calculus with Applications (10th Edition)

$2x-y=10$
Solving for y, we find the slope of $4x-2y=9:$ $-2y=-4x+9\qquad /\div(-2)$ $y=2x-\displaystyle \frac{9}{2}$ $m=2$ Our line is parallel to it and has the same slope. Use $y-y_{1}=m(x-x_{1})$ (the point-slope form) and solve for y: $y-(-4)=2(x-3)$ $y+4=2x-6$ $y=2x-10$ Rearrange into the wanted form: $y=2x-10\qquad /-y+10$ $10=2x-y$ $2x-y=10$