Answer
$2x-y=10$
Work Step by Step
Solving for y, we find the slope of $4x-2y=9:$
$-2y=-4x+9\qquad /\div(-2)$
$y=2x-\displaystyle \frac{9}{2}$
$m=2$
Our line is parallel to it and has the same slope.
Use $y-y_{1}=m(x-x_{1})$ (the point-slope form) and solve for y:
$y-(-4)=2(x-3)$
$y+4=2x-6$
$y=2x-10$
Rearrange into the wanted form:
$y=2x-10\qquad /-y+10$
$10=2x-y$
$2x-y=10$
