#### Answer

$y=-\displaystyle \frac{7}{5}x-\frac{1}{5}$

#### Work Step by Step

Start with
$y-y_{1}=m(x-x_{1})$ , the point-slope form:
slope $m$ and line passes through $(x_{1}, y_{1})$,
solve for y to obtain the form y=mx+b ,slope-intercept.
We find the slope from $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ where $x_{1}\neq x_{2}$.
$m=\displaystyle \frac{4-(-3)}{-3-2}=-\frac{7}{5}$
So, from the point-slope form:
$y-(-3)=-\displaystyle \frac{7}{5}(x-2)\quad/\times 5$ (get rid of fractions)
$5(y+3)=-7(x-2)$
$5y+15=-7x+14$
$5y=-7x-1\quad/\div 5$
$y=-\displaystyle \frac{7}{5}x-\frac{1}{5}$