## Calculus with Applications (10th Edition)

$y=-\displaystyle \frac{7}{5}x-\frac{1}{5}$
Start with $y-y_{1}=m(x-x_{1})$ , the point-slope form: slope $m$ and line passes through $(x_{1}, y_{1})$, solve for y to obtain the form y=mx+b ,slope-intercept. We find the slope from $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ where $x_{1}\neq x_{2}$. $m=\displaystyle \frac{4-(-3)}{-3-2}=-\frac{7}{5}$ So, from the point-slope form: $y-(-3)=-\displaystyle \frac{7}{5}(x-2)\quad/\times 5$ (get rid of fractions) $5(y+3)=-7(x-2)$ $5y+15=-7x+14$ $5y=-7x-1\quad/\div 5$ $y=-\displaystyle \frac{7}{5}x-\frac{1}{5}$