## Calculus with Applications (10th Edition)

Published by Pearson

# Chapter 1 - Linear Functions - Chapter Review - Review Exercises: 17

#### Answer

$$-\frac{2}{11}$$

#### Work Step by Step

The slope $m$ of a line is given by $$m=\frac{y_2-y_1}{x_2-x_1}$$ where $(x_1,y_1)$ and $(x_2,y_2)$ are two different points on the line and $x_1\neq x_2$. For a line through the origin $(0,0)$ and $(11,-2)$ $$m=\frac{-2-0}{11-0}=-\frac{2}{11}$$

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