#### Answer

$y=-x-3$

#### Work Step by Step

$y-y_{1}=m(x-x_{1})$
is the point-slope form: slope $m$ and line passes through $(x_{1}, y_{1})$.
(solve for y to obtain the form y=mx+b ,slope-intercept)
We find the slope from $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ where $x_{1}\neq x_{2}$.
$m=\displaystyle \frac{-5-3}{2-(-6)}=\frac{-8}{8}=-1$
So, from the point-slope form:
$y-3=-1[x-(-6)]$
$y-3=-x-6$
$y=-x-3$