Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 1 - Linear Functions - Chapter Review - Review Exercises - Page 40: 27



Work Step by Step

$y-y_{1}=m(x-x_{1})$ is the point-slope form: slope $m$ and line passes through $(x_{1}, y_{1})$. (solve for y to obtain the form y=mx+b ,slope-intercept) We find the slope from $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ where $x_{1}\neq x_{2}$. $m=\displaystyle \frac{-5-3}{2-(-6)}=\frac{-8}{8}=-1$ So, from the point-slope form: $y-3=-1[x-(-6)]$ $y-3=-x-6$ $y=-x-3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.