## Calculus with Applications (10th Edition)

$y=\displaystyle \frac{2}{3}x-\frac{13}{3}$
$y-y_{1}=m(x-x_{1})$ is the point-slope form: slope $m$ and line passes through $(x_{1}, y_{1})$. Solve for y to obtain the form y=mx+b (slope-intercept) $y-(-1)=\displaystyle \frac{2}{3}(x-5)$ $y+1=\displaystyle \frac{2}{3}(x-5)\qquad$/$\times$3 (get rid of fractions) $3(y+1)=2(x-5)$ $3y+3=2x-10$ $3y=2x-13\qquad /\div 3$ $y=\displaystyle \frac{2}{3}x-\frac{13}{3}$