Answer
a)$\nabla f =<2x\ln y, \frac{x^2}{y}>$
b)$\nabla f_{(3, 1)}=<0, 9>$
Work Step by Step
$\nabla f =<2x\ln y, \frac{x^2}{y}>$
$\nabla f_{(3, 1)}=<0, 9>$
$D_uf_{(3, 1)}=\nabla f_{(3, 1)}\cdot u=<0, 9>\cdot<-\frac{5}{13}, \frac{12}{13}>=\frac{108}{13}$