Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.6 - Directional Derivatives and the Gradient Vector - 14.6 Exercise - Page 957: 20

Answer

$1$

Work Step by Step

$\nabla f=\biggl$ $v=\vec{PQ}=\vec{PO}+\vec{OQ}=\big<-2, -1, -1\big>+\big<0, -3, 5\big>=\big<-2, -4, 4\big>$ $\hat{v}=\biggl<-\dfrac{2}{6}, -\dfrac{4}{6}, \dfrac{4}{6}\biggr>$ Then, $\nabla f_{(2, 1, 1)}=\biggl<1, 4, 6\biggr>$ Therefore, $\mathbf{D_\hat{v}}f_{(2, 1, 1)}=\nabla f_{(2, 1, 1)}\cdot\hat{v}=-\dfrac{2}{6} -\dfrac{16}{6}+\dfrac{24}{6}=1$
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