Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.6 - Directional Derivatives and the Gradient Vector - 14.6 Exercise - Page 957: 13

Answer

$\dfrac{7\sqrt{5}}{10}$

Work Step by Step

$\nabla f=\biggl<\sqrt{t}, \dfrac{s}{2\sqrt{t}}\biggr>$ $\hat{v}=\biggl<\dfrac{2}{\sqrt{5}}, -\dfrac{1}{\sqrt{5}}\biggr>$ Then, $\nabla f_{(2, 4)}=\biggl<2, \dfrac{1}{2}\biggr>$ Therefore, $\mathbf{D_\hat{v}}f_{(2, 4)}=\nabla f_{(2, 4)}\cdot\hat{v}=\dfrac{4}{\sqrt{5}} -\dfrac{1}{2\sqrt{5}}=\dfrac{7\sqrt{5}}{10}$
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