Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.6 - Directional Derivatives and the Gradient Vector - 14.6 Exercise - Page 957: 11

Answer

$\dfrac{4-3\sqrt 3}{10}$

Work Step by Step

Formula to calculate the directional derivative: $D_uf=f_x(x,y)a+f_y(x,y)b$ $D_uf=(e^x \sin y) \times \cos (\pi/3)+(e^x \sin y) \times \sin (\pi/3)$ This implies At $(0,\dfrac{\pi}{3})$ $D_uf (0,\dfrac{\pi}{3})=\dfrac{-6}{10} \times \dfrac{\sqrt 3}{2}+\dfrac{8}{10} \times \dfrac{1}{2}$ Hence, $D_uf (0,\dfrac{\pi}{3})=\dfrac{4-3\sqrt 3}{10}$
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