Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.6 - Directional Derivatives and the Gradient Vector - 14.6 Exercise - Page 957: 24

Answer

$\dfrac{\sqrt {17}}{2}, \lt 0,\dfrac{1}{2},2 \gt$

Work Step by Step

Formula to calculate the maximum rate of change of $f$: $D_uf=|\nabla f(x,y)|$ $\nabla f(x,y)=\lt \ln (yz)y , x/y,x/z \gt $ $\nabla f(1,2,\dfrac{1}{2})=\lt \ln 1, 1/2,2 \gt=\lt 0,\dfrac{1}{2},2 \gt$ $|\nabla f(1,2,\dfrac{1}{2})|=\sqrt{0^2+(\dfrac{1}{2})^2+2^2}=\dfrac{\sqrt {17}}{2}$ Hence, the required answers are: $\dfrac{\sqrt {17}}{2}, \lt 0,\dfrac{1}{2},2 \gt$
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