Answer
$\approx -8.83 k Pa$
Work Step by Step
The differential form of the given equation can be calculated as:
$dP=P_v dV + P_T dT$
Write the partial derivatives for the given function.
$dP=\dfrac{-8.31 T}{V^2} dV + \dfrac{8.31}{V} dT$ ...(a)
Re-arrange the above equation (a) as:
$\triangle P \approx \dfrac{-8.31 T}{V^2} \triangle V + \dfrac{8.31 T}{V} \triangle T$
and
$\triangle P \approx [\dfrac{-8.31 \times 310}{(12)^2}] \cdot (0.3) + [\dfrac{8.31}{12}] \cdot (-5)$
Thus, we get $\triangle P \approx -8.83 k Pa$
