Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.4 - Tangent Planes and Linear Approximation - 14.4 Exercise - Page 935: 35

Answer

$16 cm^3$

Work Step by Step

Volume can be calculated as: $V=\pi r^2 h$ The differential form of the given function is: $dV=(\dfrac{\partial V}{\partial r}) dr +( \dfrac{\partial V}{\partial h}) dh$ Write the partial derivatives of the given function. $dV=V_r dr+V_h dh=[ 2 \pi r h] dr+[ \pi r^2] dh$ and $dV=96 \times 3.14 \times 0.04 +16 \times 3.14 \times 0.08$ Thus, $dV \approx 16 cm^3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.