Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.4 - Tangent Planes and Linear Approximation - 14.4 Exercise - Page 935: 34

Answer

$8.792 cm^3$

Work Step by Step

Volume can be calculated as: $V=\pi r^2 h$ The differential form of the given function can be calculated as follows: $dV=(\dfrac{\partial V}{\partial r}) dr + (\dfrac{\partial V}{\partial h}) dh$ This implies that $dV=[ 2 \pi r h] dr+[ \pi r^2] dh$ $dV=2 \pi \times 2 \times 10 \times (0.05)+4 \times (0.2)$ or, $dV=2 \times 3.14 \times 2 \times 10 \times (0.05)+4 \times (0.2)$ Hence, $dV=\dfrac{14 \pi}{5} cm^3=8.792 cm^3$
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