Answer
$0.059~ohm$
Work Step by Step
The differential form of the given function is defined as:
$dR=(\dfrac{\partial R}{\partial R_1}) dR_1 + (\dfrac{\partial R}{\partial R_2}) dR_2+ (\dfrac{\partial R}{\partial R_3}) dR_3$
The above equation can be re-written as:
$\triangle R=(\dfrac{\partial R}{\partial R_1}) \times \triangle R_1 + (\dfrac{\partial R}{\partial R_2}) \times \triangle R_2+ (\dfrac{\partial R}{\partial R_3}) \times \triangle R_3=\dfrac{(11.7647)^2}{(25)^2} (0.125)+ \dfrac{(11.7647)^2}{(40)^2} (0.2)+ \dfrac{(11.7647)^2}{(50)^2} (0.25)=(138.408)[0.0002+0.000125+0.0001]=\dfrac{1}{17} $
After solving, we get
$dR \approx 0.059$ ohm
