Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise - Page 910: 8

Answer

The limit is $e^2$.

Work Step by Step

No issues arise if we evaluate the function at the given point, so the limit approaches $e^{\sqrt{2(3) - 2}} = e^{\sqrt{4}} = e^2$
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