Answer
$\sqrt 3$
Work Step by Step
Given: $\lim\limits_{(x,y,z) ) \to (\pi,0,\frac{1}{3})} e^{y^{2}}tanxz$
Substitute $x=\pi,y=0,z=\frac{1}{3}$
$=\lim\limits_{(x,y,z) ) \to (\pi,0,\frac{1}{3})} e^{0^{2}}tan\frac{\pi}{3}$
$=1\times \sqrt 3$
$=\sqrt 3$
Hence, $\lim\limits_{(x,y,z) ) \to (\pi,0,\frac{1}{3})} e^{y^{2}}tanxz=\sqrt 3$
