Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise - Page 910: 6


The limit approaches $-\frac{2}{3}$

Work Step by Step

No issues arise if we evaluate the function at the given point, so the limit approaches $\frac{(2)^2(-1) + 2(-1)^2}{2^2 - (-1)^2} = -\frac{2}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.