Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise: 7


The limit is $\frac{\pi}{2}.$

Work Step by Step

No issues arise if we evaluate the function at the given point, so the limit approaches $\frac{\pi}{2} \sin{(\pi - \pi/2)} = \frac{\pi}{2} \sin{\frac{\pi}{2}} = \frac{\pi}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.