## Calculus: Early Transcendentals 8th Edition

We notice that if we directly substitute limits in the given function $f(x,y)=\frac{5y^{4}cos^{2}x}{x^{4}+y^{4}}$ Then $f(0,0)=\frac{0}{0}$ Therefore, we will calculate limit of function in following way. To evaluate the limit along x-axis; put $y=0$ $f(x,0)=\frac{5y^{4}cos^{2}x}{x^{4}+y^{4}}=\frac{5(0)^{4}cos^{2}x}{x^{4}+0}=0$ To evaluate limit along y-axis; put $x=0$ $f(0,y)=\frac{5y^{4}cos^{2}x}{x^{4}+y^{4}}=5$ For a limit to exist, all the paths must converge to the same point. Hence, both the limits are different and follow different paths, thus, the given limit does not exist.