Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 13 - Section 13.3 - Arc Length and Curvature - 13.3 Exercise - Page 868: 7

Answer

$18.6833$

Work Step by Step

To calculate the length of the curve we will have to use the formula: $L=\int_a^b |r'(t)| dt$ Thus, $r'(t)=\lt 2t,3t^2,4t^3\gt$ and $|r'(t)|=\sqrt {( 2t)^2+(3t^2)^2+(4t^3)^2}dt$ $=\sqrt{ 4t^2+9t^4+16t^6}$ $L=\int_{0}^2(\sqrt{ 4t^2+9t^4+16t^6}) dt$ As per question, we will use calculator to find the length of the curve. Hence, $L= 18.6833$
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