## Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning

# APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises: 7

#### Answer

$2-x$

#### Work Step by Step

Start with expression given: $|x-2|,x\lt2$. Since the expression inside is negative, we must take the negative of $x-2$: $|x-2|=-(x-2)=2-x$.

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