## Calculus: Early Transcendentals 8th Edition

$x=-4,-\frac{2}{5}$
Given: $|\frac{2x-1}{x+1}|=3$ Solve the given inequality as follows: $\frac{2x-1}{x+1}=±3$ $2x-1=±3(x+1)$ $2x-1=3(x+1)$ This implies $2x-3x=3+1$ $x=-4$ or $2x-1=-3(x+1)$ This implies $2x+3x=-3+1$ $5x=-2$ $x=-\frac{2}{5}$ Hence, the solution are $x=-4,-\frac{2}{5}$