Answer
$x \leq 1~~$
The solution set is $~~(-\infty, 1]$
Work Step by Step
$x^3-x^2 \leq 0$
$x^2(x-1) \leq 0$
When $~~x=0~~$ or $~~x=1,~~$ then $~~x^2(x-1) = 0$
When $x \lt 0,~~$ then $~~x^2(x-1) \lt 0$
When $0 \lt x \lt 1,~~$ then $~~x^2(x-1) \lt 0$
When $x \gt 1,~~$ then $~~x^2(x-1) \gt 0$
Solution:
$x \leq 1~~$
The solution set is $~~(-\infty, 1]$
