## Calculus: Early Transcendentals 8th Edition

$x\geq-1$
Considering the inequality rules: $-a\geq b = a\leq-b$ and if $a>b$ then $a-c > b-c$ then: $1-x\leq2$ $=1-1 -x\leq 2-1$ $=-x\leq1$ $=x\geq-1$