## Calculus: Early Transcendentals 8th Edition

$x=-\frac{4}{3},-2$
Solve the inequality $|3x+5|=1$ $3x+5=±1$ Subtract $5$. $3x=±1-5$ This implies $3x=1-5$ or $3x=-1-5$ $3x=-4$ or $3x=-6$ Divide by 3. Hence, $x=-\frac{4}{3},-2$