Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 14 - Vector Calculus - 14.1 Vector Fields - 14.1 Exercises - Page 1058: 36

Answer

$\nabla \phi (x, y)=\lt e^{-z}, \cos (x+y) , e^{-z}, \cos (x+y), -e^{-z}, \sin (x+y) \gt$

Work Step by Step

Our aim is to compute the the gradient vector field vector. Here, we have $\phi (x, y)=e^{-z} \sin (x+y)$ Now, $\nabla \phi (x, y)=\lt \dfrac{\partial \phi (x, y)}{\partial x} , \dfrac{\partial \phi (x, y)}{\partial y} , \dfrac{\partial \phi (x, y)}{\partial z} \gt $ or, $\nabla \phi (x, y)=\lt \dfrac{\partial [e^{-z} \sin (x+y)]}{\partial x} , \dfrac{\partial [e^{-z} \sin (x+y)]}{\partial y}, \dfrac{\partial [e^{-z} \sin (x+y)]}{\partial z} \gt$ or, $= \lt e^{-z} \cos (x+y) \dfrac{\partial (x+y)}{\partial x} , e^{-z} \cos (x+y) \dfrac{\partial (x+y)}{\partial y}, e^{-z} \cos (x+y) \dfrac{\partial (x+y)}{\partial z} \gt $ Thus, we have $\nabla \phi (x, y)=\lt e^{-z}, \cos (x+y) , e^{-z}, \cos (x+y), -e^{-z}, \sin (x+y) \gt$
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