Answer
$\textbf{F} = <2xy-y^2, x^2-2yx>$
Work Step by Step
$\phi(x,y) = x^2y - y^2x$
$\textbf{F} = \nabla\phi = = <2xy-y^2, x^2-2yx>$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 14 - Vector Calculus - 14.1 Vector Fields - 14.1 Exercises - Page 1058: 29
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