Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.4 Partial Derivatives - 12.4 Exercises - Page 904: 48

Answer

$Q_{x}(x,y,z)=yz \sec^{2} xyz$ $Q_{y}(x,y,z)=xz\sec^{2} xyz$ $Q_{z}(x,y,z)=xy\sec^{2} xyz$

Work Step by Step

Treating $yz$ as a constant and differentiating with respect to $x$, we have $Q_{x}(x,y,z)=yz \sec^{2} xyz$ Holding $xz$ fixed and differentiating with respect to $y$, we get $Q_{y}(x,y,z)=xz\sec^{2} xyz$ Holding $xy$ fixed and differentiating with respect to $z$, we get $Q_{z}(x,y,z)=xy\sec^{2} xyz$
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