Answer
$$\eqalign{
& {g_x}\left( {x,y,z} \right) = 4xy - 3{z^4} \cr
& {g_y}\left( {x,y,z} \right) = 2{x^2} + 20y{x^2} \cr
& {g_z}\left( {x,y,z} \right) = - 12x{z^3} + 20{y^2}z \cr} $$
Work Step by Step
$$\eqalign{
& g\left( {x,y,z} \right) = 2{x^2}y - 3x{z^4} + 10{y^2}{z^2} \cr
& {\text{Find the first partial derivative }}{g_x}\left( {x,y,z} \right) \cr
& {g_x}\left( {x,y,z} \right) = \frac{\partial }{{\partial x}}\left[ {2{x^2}y - 3x{z^4} + 10{y^2}{z^2}} \right] \cr
& {\text{treat }}y{\text{ and }}z{\text{ as a constant}}{\text{, then }} \cr
& {g_x}\left( {x,y,z} \right) = \frac{\partial }{{\partial x}}\left[ {2{x^2}y} \right] - \frac{\partial }{{\partial x}}\left[ {3x{z^4}} \right] + \frac{\partial }{{\partial x}}\left[ {10{y^2}{z^2}} \right] \cr
& {g_x}\left( {x,y,z} \right) = 2y\frac{\partial }{{\partial x}}\left[ {{x^2}} \right] - 3{z^4}\frac{\partial }{{\partial x}}\left[ x \right] + 10{y^2}{z^2}\frac{\partial }{{\partial x}}\left[ 1 \right] \cr
& {g_x}\left( {x,y,z} \right) = 4xy - 3{z^4} \cr
& \cr
& {\text{Find the first partial derivative }}{g_y}\left( {x,y,z} \right) \cr
& {g_y}\left( {x,y,z} \right) = \frac{\partial }{{\partial y}}\left[ {2{x^2}y - 3x{z^4} + 10{y^2}{z^2}} \right] \cr
& {\text{treat }}x{\text{ and }}z{\text{ as a constant}}{\text{, then }} \cr
& {g_y}\left( {x,y,z} \right) = \frac{\partial }{{\partial y}}\left[ {2{x^2}y} \right] - \frac{\partial }{{\partial y}}\left[ {3x{z^4}} \right] + \frac{\partial }{{\partial y}}\left[ {10{y^2}{z^2}} \right] \cr
& {g_y}\left( {x,y,z} \right) = 2{x^2}\frac{\partial }{{\partial y}}\left[ y \right] - 3{z^4}\frac{\partial }{{\partial y}}\left[ x \right] + 10{z^2}\frac{\partial }{{\partial y}}\left[ {{y^2}} \right] \cr
& {g_y}\left( {x,y,z} \right) = 2{x^2} + 20y{x^2} \cr
& \cr
& {\text{Find the first partial derivative }}{g_z}\left( {x,y,z} \right) \cr
& {g_z}\left( {x,y,z} \right) = \frac{\partial }{{\partial z}}\left[ {2{x^2}y - 3x{z^4} + 10{y^2}{z^2}} \right] \cr
& {\text{treat }}x{\text{ and }}y{\text{ as a constant}}{\text{, then }} \cr
& {g_z}\left( {x,y,z} \right) = \frac{\partial }{{\partial z}}\left[ {2{x^2}y} \right] - \frac{\partial }{{\partial z}}\left[ {3x{z^4}} \right] + \frac{\partial }{{\partial z}}\left[ {10{y^2}{z^2}} \right] \cr
& {g_z}\left( {x,y,z} \right) = 2{x^2}y\frac{\partial }{{\partial z}}\left[ 1 \right] - 3x\frac{\partial }{{\partial z}}\left[ {{z^4}} \right] + 10{y^2}\frac{\partial }{{\partial z}}\left[ {{z^2}} \right] \cr
& {g_z}\left( {x,y,z} \right) = 2{x^2}y\left( 0 \right) - 3x\left( {4{z^3}} \right) + 10{y^2}\left( {2z} \right) \cr
& {g_z}\left( {x,y,z} \right) = - 12x{z^3} + 20{y^2}z \cr} $$