Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.1 Planes and Surfaces - 12.1 Exercises - Page 870: 4

Answer

$x=1$.

Work Step by Step

The equation of the plane is given by $$ 1(x-1)+1(y-0)+1(z-0) = 0 \Longrightarrow x=1.$$ So the equation is $x=1$.
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