Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.1 Planes and Surfaces - 12.1 Exercises - Page 870: 11

Answer

$$x + y - 2 - z - 2 = 0$$ $$x + y - z = 4$$

Work Step by Step

1. Write the general equation of a plane: $$a(x - x_0) + b(y - y_0) + c(z - z_0) = 0$$ 2. Substitute the values: $$ ( 1 )(x - ( 0 )) + ( 1 )(y - ( 2 )) + ( -1 )(z - ( -2 )) = 0 $$ 3. Simplify: $$x + y - 2 - z - 2 = 0$$ $$x + y - z = 4$$
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