Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.1 Planes and Surfaces - 12.1 Exercises - Page 870: 14

Answer

$$-x + 4y -3z =16$$

Work Step by Step

Step-1: Write the general equation of a plane: $$a(x - x_0) + b(y - y_0) + c(z - z_0) = 0$$ Step-2: Plug the values to obtain: $$ ( -1 )(x - 1) + 4(y -2) + ( -3 )(z+3) = 0 $$ Step-3: After simplifying, we get: $$-x +1 + 4y - 8 -3z-9 =0\\ -x + 4y -3z =16$$
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