Answer
$$-x + 2y -3z = 4$$
Work Step by Step
1. Write the general equation of a plane:
$$a(x - x_0) + b(y - y_0) + c(z - z_0) = 0$$
2. Substitute the values:
$$ ( -1 )(x - ( 2 )) + ( 2 )(y - ( 3 )) + ( -3 )(z - ( 0 )) = 0 $$
3. Simplify:
$$-x +2 + 2y - 6 -3z =0$$ $$-x + 2y -3z = 4$$
