Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.1 Planes and Surfaces - 12.1 Exercises - Page 870: 3

Answer

$(6,0,0)$.

Work Step by Step

To know where the plane $$ -2x - 3y + 4z = 12$$ intersects x-axis, we put $y=z=0$ and find the vale of $x$ that is $$ -2x=12 \Longrightarrow 3=6$$ hence the plane intersects x-axis at the point $(6,0,0)$.
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